Download PDF by Martin Dressel: Electrodynamics of Solids: Optical Properties of Electrons

By Martin Dressel

During this ebook the authors completely talk about the optical houses of solids, with a spotlight on electron states and their reaction to electrodynamic fields. Their assessment of the propagation of electromagnetic fields and their interplay with condensed topic is through a dialogue of the optical homes of metals, semiconductors, and superconductors. Theoretical strategies, dimension options and experimental effects are coated in 3 interrelated sections. the quantity is meant to be used by means of graduate scholars and researchers within the fields of condensed topic physics, fabrics technology, and optical engineering.

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In this gauge the vector potential has only a transverse component. e. 1 From Eq. 15a) we already know that the two components of the electromagnetic radiation are normal to each other: ET ⊥ BT ⊥ q. 9) to −∂ρ/∂t = ∇ ·(JL +JT ) = ∇ ·JL . 5), leads to ∇ 2A − 1 ∂ 2A 4π = − JT 2 2 c ∂t c . From the previous two relations we see that the longitudinal current density JL is only connected to the scalar potential , and the transverse current density JT is solely determined by the vector potential A. Similar relations can be obtained for the electric field.

We have included a phase factor φ to indicate that the electric and magnetic fields may be shifted in phase with respect to each other; later on we have to discuss in detail what this actually means. As we will soon see, the wavevector q has to be a complex quantity: to describe the spatial dependence of the wave it has to include a propagation as well as an attenuation part. 7d), we can separate the magnetic and electric components to obtain 1 ∂ (∇ × B) = ∇ 2 E − ∇ c ∂t 4πρext 1 . 7c), we arrive at ∇ × B = ( 1 µ1 /c)(∂E/∂t) + (4π µ1 σ1 /c)E.

Comparing Eq. 9c) with the transformed Eq. 7c), (i/µ1 )q × B(q, ω) = −(iω/c) 1 (q, ω)E(q, ω) + (4π/c)J(q, ω), we obtain for the relationship between displacement and electric field 1− 1 ω2 ω2 q × [q × E(q, ω)] − 2 1 (q, ω)E(q, ω) = − 2 D(q, ω) . 10) µ1 c c Utilizing Eq. 11) which finally leads to q2 1 − 1 µ1 = ω2 T [ (q, ω) − c2 1 L 1 (q, ω)] . 12) In the limit qc/ω → 0, both components of the dielectric constant become equal: T L 1 (0, ω) = 1 (0, ω). For long wavelength we cannot distinguish between a longitudinal and transverse electric field in an isotropic medium.

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