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By Felipe Cucker


Most artistic endeavors, even if illustrative, musical or literary, are created topic to a suite of constraints. in lots of (but no longer all) instances, those constraints have a mathematical nature, for instance, the geometric ameliorations governing the canons of J. S. Bach, a number of the projection platforms utilized in classical portray, the catalog of symmetries present in Islamic artwork, or the principles pertaining to poetic constitution. This attention-grabbing publication describes geometric frameworks underlying this constraint-based construction. the writer offers either a improvement in geometry and an outline of the way those frameworks healthy the artistic method inside of a number of paintings practices. He additionally discusses the perceptual results derived from the presence of specific geometric features. The ebook begun lifestyles as a liberal arts direction and it's definitely compatible as a textbook. even if, somebody attracted to the ability and ubiquity of arithmetic will take pleasure in this revealing perception into the connection among arithmetic and the humanities.

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Extra resources for Manifold Mirrors: The Crossing Paths of the Arts and Mathematics

Sample text

P = (a, b − q) P = (a, b) q But then we must have b − q = ma or, equivalently, b = ma + q. That is, the coordinates (a, b) of the point P satisfy the equation y = mx + q.

1 3 (3, 2) Conversely, given a name we can identify the only point on the plane having this name. If we are given the name (3, 2) we can locate the point 3 on the x-axis and draw a vertical line passing through it. Similarly, we locate the point 2 on the y-axis and draw a horizontal line parallel to the x-axis through it. The point (3, 2) is the intersection of these two lines. Again, the notion of distance – now between points on the plane – becomes visible for this system of names. Indeed, if P and Q are points in the plane with coordinates (Px , Py ) and (Qx , Qy ) respectively, then it follows from Pythagoras’ theorem that dist(P, Q) = (Px − Qx )2 + (Py − Qy )2 .

Y •... •.. ... . . . ... ....... . . . . . .. ........ ... . ..... ..... ..... • ............. ..... ..... ..... • .... ..... ..... ..... • ..... ..... ..... ..... ..... ..... .. x . . . Q m P m m O This shows that mx is the midpoint of the segment PO and, therefore, that mx = (xP + xQ )/2. And similarly for my . Note that the coordinates xP , yP , xQ , yQ for P and Q are arbitrary, but those for m are not: they are a specific expression of these four numbers, which carries over the fact that m is the midpoint of PQ.

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